The focal length of objective lens and eyepiece are 192 cm and 8 cm respectively in a small telescope calculate its magnifying power in the distance between two lenes
Answers
Answered by
3
Explanation:
Focal length of the objective lense(f_0) = 192 cm(f
0
)=192cm
Focal length of the eyepiece (f_e) = 8 cm(f
e
)=8cm
The magnifying power of the telescope (m) = f_0/ f_e = 192/8 = 24 cm(m)=f
0
/f
e
=192/8=24cm,
The separation between the objective lens and the eyepiece is = 192 + 8 = 200 cm=192+8=200cm
Similar questions