The focal length of the combination of convex lens of power 1d and a concave lens is -1.5d is
Answers
Total power of the combination of the lenses is :-
1 + (-1.5)= -0.5 D
So according to the question, we know that power =1/focal length in meters.
So focal length is 1/power=1/-0.5= -2 meters.
But focal length can't be negative, so the focal length is 2 meters and the combination of the lenses acts like a concave lens.
It is given
Power of Convex lens (P₁) = 1 d
Power of Concave lens (P₂) = -1.5d
To Find:-
Focal length of the combination (F).
Solution:-
As we know that
Power is defined as the reciprocal of its focal length.
Firstly we calculate the power of combination of lens
→ P = P¹ + P₂
Substitute the value we get
→ P = 1 + (-1.5)
→ P = 1-1.5
→ P = -0.5D
Now Calculating the Focal length of combination of lens
→ P = 1/F
Substitute the value we get
→ P = 1/F
→ -0.5 = 1/F
→ -1/0.5 = F
→ F = -2cm
Thus, The focal length of the combination of lens is -2cm or 2/100 = 0.02m