the focal length of the concave mirror is 10. an object is placed in front at the distance of 8cm find the magnifications for the image.
Answers
Answered by
1
Let magnification be m
So m= height of image/ height of object
So m= 3
Also m= -v/u (v is image distance and u is object distance
So 3 = -v/-10 ( u is negative 10 because it is always negative)
Thus v= 30
Now use the mirror formula i.e
1/f = 1/v + 1/u
And solve this
The answer is -15
So m= height of image/ height of object
So m= 3
Also m= -v/u (v is image distance and u is object distance
So 3 = -v/-10 ( u is negative 10 because it is always negative)
Thus v= 30
Now use the mirror formula i.e
1/f = 1/v + 1/u
And solve this
The answer is -15
Safwaan127:
wrong answer bud.
Answered by
3
f = -10 cm
u= -8 cm
Formula
1/v + 1/u = 1/f
1/v = 1/f - 1/u
= -1/10 - (-1/8)
= -1/10+ 1/8
= -8+10/80
= 2/80
= 1/40
v = 40
Magnification = -v/u
= -40/-8
= 5
u= -8 cm
Formula
1/v + 1/u = 1/f
1/v = 1/f - 1/u
= -1/10 - (-1/8)
= -1/10+ 1/8
= -8+10/80
= 2/80
= 1/40
v = 40
Magnification = -v/u
= -40/-8
= 5
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