Physics, asked by sbakia77, 8 months ago

The focal length of the convex len when refractive index of material n2=3/2 kept in n1=4/3 is equal to​

Answers

Answered by anshveer95
0

Answer:

Path of light rays will not change if n1=n2 and hence rays will pass through liquid lens combination un-deviated which makes lens

Answered by Rammyr
3

Answer:

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Explanation:

The focal length will become zero.

The focal length ‘f’ of a lens is given by

1/f = (n-1)[1/R1– 1/R2+(n-1)d/(nR1R2)]

where ‘n’ is the refractive index of the lens material, ‘R1’ is the radius of curvature of the lens surface closer to the light source, ‘R2’ is the radius of curvature of the lens surface farther from the light source and ‘d’ is the thickness of the lens. This formula applies if the lens is placed in air. If the lens is dipped in the liquid, then n is replaced by n1/n2 where ‘n1’ is the refractive index of the material of the lens and ‘n2’, that of the liquid. If n1=n2, n=1 and f=0. This means that parallel light rays will pass the lens without bending.

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