Physics, asked by ravinderrana1178, 1 year ago

The focal lengths of the objective and eyepiece of a microscope are 1.25 cm and 5 cm respectively. Find the position of the object relative to the objective in order to obtain an angular magnification of 30 in normal adjustment.

Answers

Answered by lAnniel
21

\huge\rm\underline\purple{Question :-}

The focal lengths of the objective and eyepiece of a microscope are 1.25 cm and 5 cm respectively. Find the position of the object relative to the objective in order to obtain an angular magnification of 30 in normal adjustment.

\huge\rm\underline\purple{Answer :-}

\green{\underline\bold{Given,}}

  • Focal length of the objective, Fo = 1.25 cm
  • Focal length of the eyepiece, Fe = 5 cm
  • Magnification,m = 30
  • Least distance of the distinct vision,D = 25 cm

\red{\underline\bold{To\:find,}}

  • The position of the object = ?

\orange{\underline\bold{We\: know\: that,}}

m = \frac{L}{Fo}(1 + \frac{D}{Fe})

⇒30 = \frac{L}{1.25}(1 + \frac{25}{5})

⇒L = \frac{30×1.25}{6}

⇒L = 6.25 cm

\pink{\underline\bold{∴\: The\: required\:answer\:is\: 6.25\: cm}}

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Answered by llTheAstheBabell
3

Answer:

your answer is6.25

hope it help

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