Question

The foci of the ellipse
$\frac{ {x}^{2} }{16} + \frac{ {y}^{2} }{ {b}^{2} } = 1$
and that of the hyperbola
$\frac{ {x}^{2} }{144} - \frac{ {y}^{2} }{81} = \frac{1}{25}$
coincide . What the value of b² ?

​

Answer 1

Refer to the attachment....

Answer 2

$\rule{300}{2}$

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R:-}}}}$

See these 2 attachments

This is the best possible answer

$\large{\boxed{\mathbf\pink{\fcolorbox{red}{yellow}{Hope\:you\:have}}}}$

$\large{\boxed{\mathbf\pink{\fcolorbox{red}{yellow}{Understood}}}}$

$<marquee>♥️Please mark it as♥️</marquee>$

$\huge\underline\mathcal\red{Brainliest}$

$</p><p>\huge{\boxed{\mathbb\green{\fcolorbox{red}{blue}{Thank\:You}}}}$

$\rule{300}{2}$