The Focus distance of a convex lens is 20 cm. How far away is an object to place from this lens so that its reflection is 2 times larger than the object, while the reflection is real?
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Explanation:
Given:
The focal length of convex lens (f) = 20cm
Magnification (m) = 2
Position of object (u) =?
Now, using the magnification formula
m = v/u
⇒ -2 = v/u
⇒ v = -2u....................(i)
Now, using lens formula
1/f = 1/v - 1/u...................(ii)
Substituting (i) in (ii)
1/20 = 1/-2u - 1/u
⇒ 1/20 = -1 - 2/2u
⇒ -3/2u = 1/20
⇒ -2u/3 = 20
⇒ u = - 20 × 3/2
⇒ u = -10 × 3
⇒ u = -30cm
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