Question

the following are the pair of linear equation x+ky-2=0,2x-6y-3=0 solve for no solution and find k?​

Answer 1

Step-by-step explanation:

Given:-

x+ky-2=0

2x-6y-3=0

To find:-

value of k

Solution:-

• here,

a1=1,b1=k,c1=2

a2=2,b2=-6,c2=3

• As we know that for no solution the law is

${:}\longrightarrow$${\boxed{{\frac{a1}{a2}}={\frac {b1}{b2}}{\cancel{=}}{\frac {c1}{c2}}}}$

${:}\longrightarrow$${\frac {1}{2}}={\frac{k}{-6}}{\cancel{=}}{\frac {2}{3}}$

${:}\longrightarrow$${\frac {k}{-6}}{\cancel{=}}{\frac {2}{3}}$

${:}\longrightarrow$$3k {\cancel{=}}-12$

${:}\longrightarrow$$k {\cancel{=}}{\frac {-12}{3}}$

${:}\longrightarrow$${\underline{\boxed{\bf {k {\cancel {=}}-4}}}}$