Physics, asked by vinaychauhan0510, 8 months ago

The following concentrations were
3
2
2
,
[N,) = 1.5 x 10-²M. [HQ] = 3.0 x10-2M and
constant.
obtained for the formation of NH from N
equilibrium at 500K.
INH,) = 1.2 x10-2M. Calculate equilibrium​

Answers

Answered by aashritaarora7
0

Answer:

The following concentrations were obtained for the formation of NH3 from N2 and H2 at equilibrium at 500K. [N2] = 1.5 × 10–2M. [H2] = 3.0 ×10–2 M and [NH3] = 1.2 ×10–2M.

Explanation:

here is your answer

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