Question

The following data given ages of 32 individual in a locality. Form a frequency distribution table.23,46,8,13,29,36,28,1,19,28,33,11,20,28,10,59,30,43,39,30,21,40,33,36,29,21,40,16,41,19,20,31
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Answer 1

Answer:

classifie this data by series that will helpful for you

Answer 2

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Here N= 32; Range = H .V.- L.V. = 59- 01 = 58 The number classes as per Sturge’s rule are: Number of class intervals (K) = 1 + 3.22 logN = 1 + 3.22 log (32) = 1+(3.22 × 1.5051) = 5.85 = 6 classes (Approx.) Size/width of class intervals – e = (Range/Number of class intervals) = 58/6 = 10 (approx). Ten size / width of each class is 10 and there are 6 classes.