Question

. The following data given the weight (in grams) of 30 oranges picked from a basket: 106, 107, 76, 109, 187, 95, 125, 92, 70, 139, 128, 100, 88, 84, 99, 113, 204, 141, 136, 123, 90, 115, 110, 97, 90, 107, 75, 80, 118, 82. Construct a grouped frequency distribution table taking class width equal to 20 in such a way that mid-value of first class in 70 From the frequency table, find the number of oranges i. Weighing more than 180 grams ii. Less than 100 gram

Answer 1

Answer:

Here , class width = 20

class mark = 70

Half of the class width =20 /2 =10

Upper limit of first class interval = 70 + 10 = 80

Lower limit of first class interval = 70 – 10 = 60

Thus, class interval becomes 60 – 80

So, frequency distribution table becomes :

(a) Number of oranges weights more than 180 g = 1 + 1 = 2

(b) Number of oranges weights less than 100 g = 3 + 10 = 13

Answer 2

Answer:

1. The number of oranges weighing more than 180 g = 2

2. The number of oranges weighing less than 100 g = 13

Step-by-step explanation:

Step 1:

First we have to determine the class groups.

The mid-value of first class: 70

Hence, the first class: 60-80

Next class groups will be in the class width of 20.

Step 2:

The frequency distribution table is attached in the image.

Step 3:

Number of oranges weighing more than 180 g = f(180-200) + f(200-220)

= 1 + 1

= 2

Step 4:

Number of oranges weighing less than 100 g = f(60-80) + f(80-100)

= 4 + 9

= 13

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