Question

The following data gives information on the observed lifetimes (in hours) of 225 electrical

components Determine the modal lifetimes of the components.

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Answer 1

Solution:-

$mode = l + \frac{f0 - f1}{2f0 - f1 - f2} \times h$

$l = 60 \\ h = 20 \\ fo = 52 \\f 1 = 61\\ f2 = 38$

$mode = 60 + \frac{61 - 52}{2 \times 61 - 52 - 38} \times 20 \\ = 60 + \frac{9}{32} \times 20 \\ = 60 + 5.62 \\ = 65.62$

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Answer 2

Answer:

65.625

Step-by-step explanation:

mode = $L+(\frac{F1-F0}{2F1-F0-F2} )$ × H

L = Lower limit

H = Class size

F 1 = Frequency of the modal class

F 0 = Frequency of the preceding modal class

F 2 = Frequency of the succeeding modal class

$60+(\frac{61-52}{2(61)-52-38})$ × H

$60+(\frac{9}{122-52-38} )$ × 20

$60 + (\frac{9}{32} )$ × 20

$60+(\frac{45}{8} )\\\\60+5.625\\\\= 65.625$