Math, asked by mf7694339, 1 month ago

The following data related with the prices of
items in Jabalpur and Narsinghpur are available.
Estimate the price of item in Narsinghpur when
the price in Jabalpur is 15:
Jabalpur Narsinghpur
Mean of the prices
of the item
10
12
Standard Deviation of
the prices of the item 4.2
4.5
The correlation coefficient between the prices
of item in Jabalpur and Narsinghpur = +0.8​

Answers

Answered by amitnrw
0

Given :                                Jabalpur     Narsinghpur

Mean of the prices of the item    10             12

SD of the prices of the item         4.2            4.5

To Find :  Estimate the price of item in Narsinghpur when the price in Jabalpur is 15

Solution:

x   Jabalpur  Mean = 10  ,  SD = 4.2

y  Narsinghpur  Mean = 12   ,  SD = 4.5

y = (byx ).x  + c

byx =  r σy/σx  = 0.8 (4.5)/4.2  =    6/7

y - ymean = (byx ) (x - xmean)

y - 12 = (6/7)(x - 10)

=> 7y - 84 = 6x - 60

=> 7y = 6x + 25

=> y = 6x/7  + 24/7

x = 15

=> y = 6(15)/7  + 24/7

=> y = 114/7  = 16.2857

the price of item in Narsinghpur  is  16.2857 when the price in Jabalpur is 15

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