The following distribution gives the daily wages of 50 workers of a factory.
Daily wages (in Rs.) No. of workers
150-200 8
200-250 12
250-300 14
300-350 10
350-400 06
Find the median of above data.
Answers
Answer:
answer
Step-by-step explanation:
Let’s find mean of the data using assumed mean method.
We are using assumed mean method to avoid miscalculation and false answer, as xi's are large in this question.
First, construct a table for ease of calculation.
Mean is given by
\bf{Mean=A+\frac{\Sigma f_id_i}{\Sigma f_i}}Mean=A+
Σf
i
Σf
i
d
i
Where A = assumed mean
\bf{Mean=325+\frac{-600}{50}}Mean=325+
50
−600
Mean = 325 – 12 = 313
Thus, mean daily wages of the workers is Rs. 313.
Step-by-step explanation:
solution:-
Sum of all frequencies (n)=50
n/2 = 50/2 = 25
n/2 = 25
Median class = 250-300
Lower limit of the median class (l)=250
Cumulative frequency of the class preceding the
median class (cf)=20
Class size (h)=50
Frequency of the median class (f)=14
Median of the data (M)=l+[(n/2 - cf)/f]×h
=>M = 250+[(25-20)/14]×50
=>M= 250+(5/14)×50
=>M = 250+(250/14)
=>M = 250+ 17 .85
=>M = 267.85
Answer:-
Median for the given dat is Rs. 267.85
Used formulae:-
- Median of the data (M)=l+[(n/2 - cf)/f]×h
Where,
- M= Median
- l= lower limit of the median class
- n= Sum of all frequencies
- cf=Cumulative frequency of the class preceding the median class
- f=frequency of the median class
- h=class size