Math, asked by parul422, 1 month ago

The following distribution gives the daily wages of 50 workers of a factory.

Daily wages (in Rs.) No. of workers

150-200 8

200-250 12

250-300 14

300-350 10

350-400 06

Find the median of above data.​

Answers

Answered by hvkhairnarfamily
2

Answer:

answer

Step-by-step explanation:

Let’s find mean of the data using assumed mean method.

We are using assumed mean method to avoid miscalculation and false answer, as xi's are large in this question.

First, construct a table for ease of calculation.

Mean is given by

\bf{Mean=A+\frac{\Sigma f_id_i}{\Sigma f_i}}Mean=A+

Σf

i

Σf

i

d

i

Where A = assumed mean

\bf{Mean=325+\frac{-600}{50}}Mean=325+

50

−600

Mean = 325 – 12 = 313

Thus, mean daily wages of the workers is Rs. 313.

Answered by tennetiraj86
0

Step-by-step explanation:

solution:-

Sum of all frequencies (n)=50

n/2 = 50/2 = 25

n/2 = 25

Median class = 250-300

Lower limit of the median class (l)=250

Cumulative frequency of the class preceding the

median class (cf)=20

Class size (h)=50

Frequency of the median class (f)=14

Median of the data (M)=l+[(n/2 - cf)/f]×h

=>M = 250+[(25-20)/14]×50

=>M= 250+(5/14)×50

=>M = 250+(250/14)

=>M = 250+ 17 .85

=>M = 267.85

Answer:-

Median for the given dat is Rs. 267.85

Used formulae:-

  • Median of the data (M)=l+[(n/2 - cf)/f]×h

Where,

  • M= Median
  • l= lower limit of the median class
  • n= Sum of all frequencies
  • cf=Cumulative frequency of the class preceding the median class
  • f=frequency of the median class
  • h=class size

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