Question

The following figure shows \triangle ABC△ABCtriangle, A, B, C with side lengths to the nearest tenth.
Triangle ABC. Side AB measures 5 units. Angle B is 130 degrees and angle C is 24 degrees.
Triangle ABC. Side AB measures 5 units. Angle B is 130 degrees and angle C is 24 degrees.
Find BCBCB, C in \triangle ABC△ABCtriangle, A, B, C.
Round to the nearest tenth.
BC={}BC=

Answer 1

Answer:

how cab we find BCBCB please correct your question

Answer 2

Answer: The answer is 1.9 units.

Explanation: To find the length of side BC in triangle ABC, we can use the law of sines, which states that for any triangle with sides a, b, and c and opposite angles A, B, and C, the following relationship holds:

• a/sin A = b/sin B = c/sin C

We are given side AB and angles B and C, so we can use the law of sines to find the length of side BC. Let x be the length of BC, then:

• 5/sin 130 = x/sin 24

Simplifying, we get:

• x = 5*sin 24 / sin 130

Using a calculator, we can evaluate this to be approximately 1.9 units. Therefore, BC is approximately 1.9 units (rounded to the nearest tenth).

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