The following is a pair of linear equations :
4x + 3y = 3
(2k+3)x + (2k+1 ) y = 4(k-1)
Answer the following questions with reference to the giv
Write down the condition for infinitely many solutions
Find the value of K
Answers
Answered by
5
The condition for infinite solution is :
a1/a2 = b1/b2 = c1/c2
Using it,
4/(2k+3) = 3/(2k+1) = -3/-4(k-1)
4(2k+1) = 3(2k+3) (use 1st and 2nd only)
8k + 4 = 6k + 9
2k = 5
k = 5/2
So k = 5/2
Hope it helps
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a1/a2 = b1/b2 = c1/c2
Using it,
4/(2k+3) = 3/(2k+1) = -3/-4(k-1)
4(2k+1) = 3(2k+3) (use 1st and 2nd only)
8k + 4 = 6k + 9
2k = 5
k = 5/2
So k = 5/2
Hope it helps
pls mark as brainliest
Answered by
1
Answer:
Step-by-step explanation:The condition for infinite solution is :
a1/a2 = b1/b2 = c1/c2
Using it,
4/(2k+3) = 3/(2k+1) = -3/-4(k-1)
4(2k+1) = 3(2k+3) (use 1st and 2nd only)
8k + 4 = 6k + 9
2k = 5
k = 5/2
So k = 5/2
Hope it helps
pls mark as brainliest
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