Question

the following no are arranged in ascending order have mean and median same 4 ,4,x-2,x+1,x+3,12,13 find x and median​

Answer 1

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.∵n=9(odd)

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.∵n=9(odd)∴ Median=2n+1th term

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.∵n=9(odd)∴ Median=2n+1th term=29+1th term

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.∵n=9(odd)∴ Median=2n+1th term=29+1th term24=5th term

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.∵n=9(odd)∴ Median=2n+1th term=29+1th term24=5th term∴x+4=24

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.∵n=9(odd)∴ Median=2n+1th term=29+1th term24=5th term∴x+4=24x=24−4

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.∵n=9(odd)∴ Median=2n+1th term=29+1th term24=5th term∴x+4=24x=24−4x=20

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.∵n=9(odd)∴ Median=2n+1th term=29+1th term24=5th term∴x+4=24x=24−4x=20Therefore, 11,12,14,(20−2),(20+4),(20+9),32,38,47=11,12,14,18,24,29,32,38,47

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.∵n=9(odd)∴ Median=2n+1th term=29+1th term24=5th term∴x+4=24x=24−4x=20Therefore, 11,12,14,(20−2),(20+4),(20+9),32,38,47=11,12,14,18,24,29,32,38,47Now Mean=n∑x

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.∵n=9(odd)∴ Median=2n+1th term=29+1th term24=5th term∴x+4=24x=24−4x=20Therefore, 11,12,14,(20−2),(20+4),(20+9),32,38,47=11,12,14,18,24,29,32,38,47Now Mean=n∑x=911+12+14+18+24+29+32+38+47

Given observation are 11,12,14,(x−2),(x+4),(x+9),32,38,47 and median =24.∵n=9(odd)∴ Median=2n+1th term=29+1th term24=5th term∴x+4=24x=24−4x=20Therefore, 11,12,14,(20−2),(20+4),(20+9),32,38,47=11,12,14,18,24,29,32,38,47Now Mean=n∑x=911+12+14+18+24+29+32+38+47=9225=25