the following obs. 29,32,48,x-2,x,x+2,72,78,84,95,have been arranged in assending order. if the median of the data is 63. find te value of x
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Hi ,
Given observations are ,
29 , 32 , 48. x - 2 , x , x + 2 , 72 , 78 , 84 , 95
number of observations ( n ) = 10 ( even )
median = Ave( n/2 , n/2 + 1 ) th terms
= Ave( 5th , 6th ) terms
= ( x + x + 2 )/2
= ( 2x + 2 )/2
= x + 1 ----( 1 )
median = 63 ( given ) ----( 2 )
from ( 1 ) & ( 2 ) , we get
x + 1 = 63
x = 62
I hope this helps you.
: )
Given observations are ,
29 , 32 , 48. x - 2 , x , x + 2 , 72 , 78 , 84 , 95
number of observations ( n ) = 10 ( even )
median = Ave( n/2 , n/2 + 1 ) th terms
= Ave( 5th , 6th ) terms
= ( x + x + 2 )/2
= ( 2x + 2 )/2
= x + 1 ----( 1 )
median = 63 ( given ) ----( 2 )
from ( 1 ) & ( 2 ) , we get
x + 1 = 63
x = 62
I hope this helps you.
: )
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