Physics, asked by shedoesntevengohere8, 1 year ago

The following resistors (one each) are connected in a series circuit. 1, 2, 5, 12 and 22 Ω. Determine the total resistance.

Answers

Answered by aadi7571

0

total resistance of series circuit

R = R1 + R2 + R3 + R4 + R5

=> R = 1 + 2 + 5 + 12 + 22

=> R = 32 ohm

Answered by aadesh25

0

Rs = r1 +r2 + r3 + r4

Rs = 1+2+5+12+22

Rs= 42 ohm

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