The following resistors (one each) are connected in a series circuit. 1, 2, 5, 12 and 22 Ω. Determine the total resistance.
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total resistance of series circuit
R = R1 + R2 + R3 + R4 + R5
=> R = 1 + 2 + 5 + 12 + 22
=> R = 32 ohm
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Rs = r1 +r2 + r3 + r4
Rs = 1+2+5+12+22
Rs= 42 ohm
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