Question

The following resistors (one each) are connected in a series circuit. 1, 2, 5, 12 and 22 Ω. Determine the total resistance.

Answer 1

Answer:

Since the resistors are connected in series, the equivalent resistance would be 1+2+5+12+22=42 ohm

Answer 2

Explanation:

As the resistors are connected in series.so we add it 1+2+5+12+22 = 42

The total resistance is 42 Ohms