the following simultaneous equat
(1) 2x + 3y = 12; x - y =1
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2x + 3y = 12 ........i)
x - y = 1 ........ii)
We will apply the elimination method,
so will add both,
2x + 3y = 12
3x - 3y = 3 ( multiplying ii) by 3 )
5x = 15
=> x = 3
substituting the value of x in i),
=> 2 × 3 + 3y = 12
=> 6 + 3y = 12
=> 3y = 6
=> y = 2
therefore, the value of x = 3 and y = 2;
I hope it maybe helpful!!
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