Question

the folowing distribution of the daily pocket allowance of children of a lacality the mean pocket allowance is Rs 18. find the missng frequancy f.​

Answer 1

F=20

x=sum of fi*xi/sum of fi

x=18 , sum of fi*xi = 20f+752 , sum of fi = 44+f

then

18/1=20f+752/44+f. (cross multiplication)

20f+752 = 18(44+f)

20f -18f = 792 -752

2f =40

f=40/2

therefore (f=20)