the foot of a ladder is 6m away from a wall and its top reaches a window 8m above the ground. if the ladder is shifted in such a way that its foot is 8m away from the wall, to what height does its top reach?
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Answer:
Step-by-step explanation:
Apply tan theta
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1
Answer:
Length of ladder=v8^2+6^2 = 10
.height=v10^2-8^2 = 6m
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