Question

The Force acting between two point charges kept at a certain distance is F. Now
magnitude of charges is doubled and distance between them is halved, the Force acting between them is.

Answer 1

Explanation:

ANSWER

According to Coulomb's law, force between two charge particle q

1

and q

2

at a distance r is

r

2

Kq

1

q

2

.

Given, Initial Force = 5N =

r

2

Kq

1

q

2

.

Now, Q

1

= 2q

1

and Q

2

= 2q

2

and R=

2

r

. Now , Force =

R

2

KQ

1

Q

2

=

r

2

2×2×K2q

1

2q

2

= 16×

r

2

Kq

1

q

2

= 16×5N = 80N.