Question

The force acting between two point charges kept at a certain distance is . Now magnitudes of charges
are doubled and distance between them is halved, the force acting between them is.....
​

Answer 1

Answer:

According to Coulomb's law, force between two charge particle q

1

and q

2

at a distance r is

r

2

Kq

1

q

2

.

Given, Initial Force = 5N =

r

2

Kq

1

q

2

.

Now, Q

1

= 2q

1

and Q

2

= 2q

2

and R=

2

r

. Now , Force =

R

2

KQ

1

Q

2

=

r

2

2×2×K2q

1

2q

2

= 16×

r

2

Kq

1

q

2

= 16×5N = 80N.

Therefore, D is the correct option.

Answer 2

Answer:

8times increases

Explanation:

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