Question

the force between two charges ina vacuum is 0.1 N.what is the force if the vacuum is replaced by a medium of permittivity 10 times greater than that of vacuum​

Answer 1

Answer:

0.01N

Explanation:

we know that

F = (1/4πE).q1q2/r²

We see that F is inversely proportional to permittivity

so,

If the permittivity is increased ten times, the force will decrease ten times.

F = k/E

A/Q, E' = 10E, then

F' = k/E' = k/10E = F/10 = 0.1N/10 = 0.01N.