Question

The force between two charges separated by a
distance 1 m is 1.8 N. The charges are in the
ratio 1:2 then the charges are
1) 54C, MC
2) 5uC,10uC
3) ΤμC,10μC
4) 10uC,20uc​

Answer 1

Explanation:

F=K q1q2/r²

K=9×10⁹

F=1.8N

Q1:Q2=1:2

then,2Q1=Q2,Q1=Q1

r=1m

F=kQ1Q2/r²

1.8=9×10⁹ × 2Q1.Q1/1²

1.8=18Q²1×10⁹

Q1²=1.8/18×10^9

Q1²=1/10^10

Q1=1/10⁵=10^-5C (taking square root)

10^-5×10^6=10uC

Q2=2Q1

Q2=20uC