Question

the force between two charges when separated by a distance of 50 cm in air is 40
Newton what will be the force between them is the distance becomes 25​

Answer 1

I think this is right.....

Answer 2

Given that,

Force between two charges is 40 N when placed at a distance of 50 cm.

To find,

The force when the distance becomes 25​ cm.

Solution,

The force between charges is inversely proportional to the square of distance between them such that :

$\dfrac{F_1}{F_2}=(\dfrac{r_2}{r_1})^2$

F₂ is force at a distance of 25 cm

$F_2=\dfrac{F_1r_1^2}{r_2^2}\\\\F_2=\dfrac{40\times (50)^2}{(25)^2}\\\\F_2=160\ N$

So, the new force becomes 160 N.

Learn more,

Electric force

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