Question

The force between two electrons when placed in air is equal to 0.5 times of weight of an electron. Find the distance between two electrons ​

Answer 1

$<b><i>here's your answer$

$according\: to\: the\: question$

F͟͟o͟͟r͟͟c͟͟e͟͟ b͟͟e͟͟t͟͟w͟͟e͟͟e͟͟n͟͟ t͟͟w͟͟o͟͟ e͟͟l͟͟e͟͟c͟͟t͟͟r͟͟o͟͟n͟͟s͟͟ w͟͟h͟͟e͟͟n͟͟ p͟͟l͟͟a͟͟c͟͟e͟͟d͟͟ i͟͟n͟͟ a͟͟i͟͟r͟͟

= 0.5 × w͟͟e͟͟i͟͟g͟͟h͟͟t͟͟ o͟͟f͟͟ e͟͟l͟͟e͟͟c͟͟t͟͟r͟͟o͟͟n͟͟

F͟͟o͟͟r͟͟ f͟͟i͟͟n͟͟d͟͟i͟͟n͟͟g͟͟ d͟͟i͟͟s͟͟t͟͟a͟͟n͟͟c͟͟e͟͟ ,

=$9 \times {10}^{9} \times \frac{1.6 \times 10 { }^{ - 19} \times 1.6 \times 10 {}^{ - 19} }{ {r}^{2} }$

=$0.5 \times 9.1 \times 10 {}^{ - 31} \times 9.8$

r = 7.2 i͟͟s͟͟ t͟͟h͟͟e͟͟ a͟͟n͟͟s͟͟w͟͟e͟͟r͟͟ .

T͟͟h͟͟a͟͟n͟͟k͟͟s͟͟!!

Answer 2

Answer:

7.2

Explanation:

Electrostatic force F e=ke2/r2

weight of elextron w=mg

so,F e=0.5W

OR

ke2/r2=0.5mg

OR

9×10*9(1.6×10*-9)*2/r*2=0.5×9.1×10*-31×10

r=7.2