the force constant of 14N16O is 1550N/m.predict it's bond order, calculate reduced mass, fundamental frequency in 1/cm
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Nitrogen forms : N ≡ N
, Oxygen forms: O = O
N: 2s2 2p3 O: 2s2 2p4
Bond order for ¹⁴N - ¹⁶O bond:
= (number of bonding electrons - number of antibonding electrons)/2
= [ (2 from N +4 from O) - 1 from N ] / 2 = 2.5
m1 = 14u m2 = 16u
reduced mass = μ = m1 * m2 / (m1 + m2)
= 112/15 = 7.47 u
μ = 7.47 * 0.001 kg / 6.023 * 10²³ = 1.239 * 10⁻²⁶ kg
k = force constant = 1150 N/m
c = speed of light = 3 * 10¹⁰ cm/s
The fundamental frequency of oscillation of N & O atoms about the center of mass is given by: f = 1/2π * √(k/μ) in Hz
f = 1/(2π c) * √(k/μ) in cm⁻¹ = wavenumber of the oscillation
= 1 876 cm⁻¹
N: 2s2 2p3 O: 2s2 2p4
Bond order for ¹⁴N - ¹⁶O bond:
= (number of bonding electrons - number of antibonding electrons)/2
= [ (2 from N +4 from O) - 1 from N ] / 2 = 2.5
m1 = 14u m2 = 16u
reduced mass = μ = m1 * m2 / (m1 + m2)
= 112/15 = 7.47 u
μ = 7.47 * 0.001 kg / 6.023 * 10²³ = 1.239 * 10⁻²⁶ kg
k = force constant = 1150 N/m
c = speed of light = 3 * 10¹⁰ cm/s
The fundamental frequency of oscillation of N & O atoms about the center of mass is given by: f = 1/2π * √(k/μ) in Hz
f = 1/(2π c) * √(k/μ) in cm⁻¹ = wavenumber of the oscillation
= 1 876 cm⁻¹
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