the force exerted on a partivle with a charge of 5.0 ×10^-9 C by a second particle that is 4 cm away is 8.4105 N . What is the charge of the second particle?
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Answered by
2
Answer:
use formula F=k (Q1×Q2)/radius^2
put F as force
Q1 as given charge
k = 1/(4π€°)
r=radius
Answered by
1
Answer:2.99×10^-4
Explanation:F=q1q2 ÷4π€•r²
F=8.4105
q1=5×10^-9
q2=?
r=4×10^-2
€•=8.85×10^-12
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