Question

the force exerted on a partivle with a charge of 5.0 ×10^-9 C by a second particle that is 4 cm away is 8.4105 N . What is the charge of the second particle?
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Answer 1

Answer:

use formula F=k (Q1×Q2)/radius^2

put F as force

Q1 as given charge

k = 1/(4π€°)

r=radius

Answer 2

Answer:2.99×10^-4

Explanation:F=q1q2 ÷4π€•r²

F=8.4105

q1=5×10^-9

q2=?

r=4×10^-2

€•=8.85×10^-12