Question

The force exerted on an object is F=fo(x/a-1)Find the work done in moving the object from x =O to x = 3a.​

Answer 1

Explanation:

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Answer 2

Answer:

The work done in moving the object is $f_{0}(\dfrac{3}{2}a)$.

Explanation:

Given that,

Force $F=f_{0}(\dfrac{x}{a}-1)$

We need to calculate the work done

Using formula of work done

$W=F.d$

$F.d=\int_{x}^{x'}{f_{0}(\dfrac{x}{a}-1)}$

$W=f_{0}(\int_{0}^{3a}{f_{0}(\dfrac{x}{a}-1)})$

$W=f_{0}({\dfrac{x^2}{2a}-x}_{0}^{3a})$

$W=f_{0}({\dfrac{9a^2}{2a}-3a-0})$

$W=f_{0}(\dfrac{3}{2}a)$

Hence, The work done in moving the object is $f_{0}(\dfrac{3}{2}a)$.