Question

The force experienced by a particle having mass m charge q accelerated through a potential
diference V when it is kept under perpendicular magnetic field B is ​

Answer 1

Answer:

magnetic force on charge particle can be found by formula:

F=q(v*B)

F=qvBsinθ

Answer 2

Answer:

The magnetic field B will make the charged particle with "mass m" and "charge q" to take a circular path with the centripetal force. Since the magnetic field is "perpendicular to the velocity" of the charged particle, at equilibrium, the magnetic force equals the centripetal force.

Given:

Mass of the charged particle – m

Charge – q

Potential difference - V

Magnetic field – B

According to Lorenz Force Law,  

The force is "perpendicular to the velocity" of the charged particle and the magnetic field.

So the magnitude of force F:

$\mathrm{F}=\mathrm{gVB} \sin \theta$ where $\theta$ is the angle between the velocity and magnetic field and is < 180 degrees.