The force F acting on a particle in terms of time t and
distance x is given by F = (A cos Bx) (C sin Dt).
The dimensions of AC and BD are :
(a) [MLT-?], [Mº L-1 Tl)
(b) [MLT-?], [M1T-l,
(c) [ML?T?], [Mºl-112
(d) [ML T-?], [M° 1-1 T-l].
Answers
Answered by
3
Answer:
F=A cosBx+C sinDt
the argument, θ of cos or sin should be dimensionless.
therefore,
dimension of Bx = [MLT]
[B][L
′
]=[MLT]
[B]=[ML
0
T]
Similarly [D][T
′
]=[MLT]
[D]=[MLT
0
dimension of DB=
[ML
0
T]
[MLT
0
]
= [L
1
T
−1
]
Answered by
4
Answer:
F=A cosBx+C sinDt
the argument, θ of cos or sin should be dimensionless.
therefore,
dimension of Bx = [MLT]
[B][L
′
]=[MLT]
[B]=[ML
0
T]
Similarly [D][T
′
]=[MLT]
[D]=[MLT
0
dimension of DB=
[ML
0
T]
[MLT
0
]
= [L
1
T
−1
]
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