Question

The force F acting on a particle moving in a straight line is shown in figure. What is the work done by the force on the particle in the 1st meter of the trajectory?

Answer 1

$\underline{\bold{Given:-}}$

Force = 5N

Displacement = 1 m

$\underline{\bold{To\:find:-}}$

Work done

$\underline{\bold{Solution:-}}$

Work done is defined as the product of force and displacement.

Work done = Force × Displacement

= 5 × 1

= 5 Joule

So, 5 Joule work is done when 5N force is applied for a distance of 1 m.

Answer 2

The formula for getting work is as follows :

Work = Force × distance

The force is given in the question as = 5 N

Distance is the first meter of trajectory = 1 Meter

We do the substitution as follows to get the work done.

Force = 5

The work done is thus :

Work = 5 × 1 = 5

5 Joules.

The answer is therefore given as 5 Joules