The force, F Newtons, exerted by a magnet on a metal object is inversely proportional to the square of the distance d cm.
When d=2 cm, F= 50 N
(A) Express F in terms of d.
(B) Find the force when the distance between the magnet and metal is 10cm.
Can someone help my poor brain cells?
Answers
Answer:
Solution−
Let assume that
Speed of the train be x km per hour
Speed of the car be y km per hour
Case :- 1
A man travels 600km apart by train and partly by car. It takes 8 hours and 40 minutes if he travels 320 km by train and rest by car.
Distance travelled by train = 320 km
So,
Distance travelled by car = 600 - 320 = 280 km
Time taken = 8 hr 40 min
So,
\begin{gathered}\rm \: \dfrac{320}{x} + \dfrac{280}{y} = 8\dfrac{40}{60} \\ \end{gathered}
x
320
+
y
280
=8
60
40
\begin{gathered}\rm \: \dfrac{320}{x} + \dfrac{280}{y} = 8\dfrac{2}{3} \\ \end{gathered}
x
320
+
y
280
=8
3
2
\begin{gathered}\rm \: \dfrac{320}{x} + \dfrac{280}{y} = \dfrac{26}{3} - - - (1) \\ \end{gathered}
x
320
+
y
280
=
3
26
−−−(1)
Answer:
mark me as brainliest
Step-by-step explanation:
The force, F newtons, exerted by a magnet on a metal object is inversely
proportional to the square of the distance d cm.
When d = 2 cm, F= 50 N.
Express F in terms of d.
Answer:
F = 200/d^2
Step-by-step explanation:
F is inversely proportional to d^2
The equation is;
F = k/d^2
K = F•d^2
so to get k, we substitute the given values
K = 50 * 2^2
K = 50 * 4
K = 200
So we have that;
F * d^2 = 200
F = 200/d^2