The force Fı parallel to inclined plane
that is necessary to move a body up an
inclined plane is double the force F2 that
is necessary to just prevent it from
sliding down, then:
Where 0 = Limiting angle of repose,
0 = angle of inclined plane, w = weight
of the body
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2
Answer:
Let the max friction be f
Case 1: body is just about to move up
friction and gravitational force will act in downward direction so
2F=mgsinθ+f ...1
Case 2; body is just prevented to slip
Friction will act upwards and gravitation will act downwards
F=mgsinθ−f ..2
Using equation 1 and 2
mgsinθ−3f=0
max friction=μmgcosθ
∴mgsinθ=3μmgcosθ
∴tanθ=3μ
θ=tan
−1
3μ
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