Question

the force of 1200 Newton acts on a surface of area 10 cm square normally what would be the thrust and pressure on the surface

Answer 1

Hey there!

Given,

Force(F) = 1200 N

Area (A) = 10 cm² = 0.001 m²

We know,

Thrust is the force acting normally to a surface.

So, Thrust = 1200 N

And, Pressure = Thrust / Area

                        = 1200 / 0.001

                       = 1200000 Pa

                       = 1.2 × 10⁶ Pa

Hope it Helps You!

Answer 2

Answer:

The surface thrust and pressure are 1200 N and 12×10⁴ Pascal, respectively.

Explanation:

To answer this question, we utilize the following equation:

$P=\frac{Thrust}{A}$         (1)

Where,

P=pressure acting over an area

Thrust= force acting on a cross-section

A=area over which the force is acting

From the question we have,

The force acting=1200N

Side of square(l)=10cm=0.1m

The square's area is calculated as follows:

$A=l^2$    

So,

$A=(0.1)^2$

$A=0.01m^2$     (2)

The thrust on the surface will be =1200N

By putting the relevant variables into equation (1), we get the following results:

$P=\frac{1200}{0.01}$

$P=1200\times 10^2$

$P=12\times 10^4\ Pascal$

Hence, the thrust and pressure on the surface are 1200 N and 12×10⁴ Pascal respectively.

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