detect the presence of nitrogen atom in a given organic compound O
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The carbon and nitrogen present in the organic compound on fusion with sodium metal gives sodium cyanide (NaCN) soluble in water. This is converted in to sodium ferrocyanide by the addition of sufficient quantity of ferrous sulphate. Ferric ions generated during the process react with ferrocyanide to form prussian blue precipitate of ferric ferrocyanide.
Na + C + N → NaCN
6NaCN + FeSO4 → Na4[Fe(CN)6] + Na2SO4
Sodium ferrocyanide
Na4[Fe(CN)6] + Fe3+ → Fe4[Fe(CN)6]3
Ferric ferrocyanide
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Na + C + N → NaCN
6NaCN + FeSO4 → Na4[Fe(CN)6] + Na2SO4
Sodium ferrocyanide
Na4[Fe(CN)6] + Fe3+ → Fe4[Fe(CN)6]3
Ferric ferrocyanide
Hope this will be helpful to you...
Plz mark it as brainliest
Anonymous:
This question is from experiment examination i don't thing so it is good for me
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Heya! Here's ur answer:-
Carbon and Nitrogen which is present in the organic compound on fusion with sodium gives sodium cyanide(NaCN) which is soluble in water.This gets converted to ferrous sulphate.Then ferric ions are generated during the reaction with ferrous cyanide to form Prussian blue precipitate of ferrous cyanide.
Na+C+N ->NaCN
6NaCN+FeSO4 ->Na4[Fe(CN)6]+Na2SO4
Sodium ferrous cyanide
Na4[Fe(CN)6]+Fe3->Fe4[Fe(CN)6]
Ferric Cyanide
Carbon and Nitrogen which is present in the organic compound on fusion with sodium gives sodium cyanide(NaCN) which is soluble in water.This gets converted to ferrous sulphate.Then ferric ions are generated during the reaction with ferrous cyanide to form Prussian blue precipitate of ferrous cyanide.
Na+C+N ->NaCN
6NaCN+FeSO4 ->Na4[Fe(CN)6]+Na2SO4
Sodium ferrous cyanide
Na4[Fe(CN)6]+Fe3->Fe4[Fe(CN)6]
Ferric Cyanide
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