Question

128352/238368 lowest terms

Answer 1

Lowest term:1337/2483

HOW:
____

FIRST ,DIVISIBILITY OF 2:
check if last digit of both denominator and numerator are even numbers if so it is possible to divide it completely by 2. by doing so we came until 4011 & 7449 which are not divisible by 2 since its last digits r not even.So ,DIVISIBILITY TEST OF 3:
check if sum of digits of numerator and dinominator seperaly are divisible by three.
This test became applicable here and v shortened the fraction untill v obtained the lowest term:1337/2483