The force of attraction between two bodies at a
certain separation is 10 N. What will be the force
of attraction between them if the separation is
reduced to half ?
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Answer:
hy
Explanation F=10N;
F=GMm/R2
Let the new distance be R
where, F= Gravitational force
m1 ,m2 = Masses of two bodies
r= Distance
G=Gravitaional constant =6.673×10^-11 Nm2/ kg −2
From the above equation we can conclude that if distance between the object is reduceed to half then force would become four times.
Therefore, F
g ′=4×Fg
so new force =40 N
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