Question

The force of gravitation between objects of ordinary size
kept at a distance of 1m from each other is of the order of
(a) 10 N
(b) 100 N
(c) 10-8 N .
(d) 10-11N​

Answer 1

Given that,

Distance between two objects of ordinary size is 1 m

To find,

The order of force of gravitation.

Solution,

Let masses are 1 kg each and the distance between them is 1 m. The gravitational force is given by :

$F=\dfrac{Gm^2}{r^2}\\\\F=\dfrac{6.67\times 10^{-11}\times 1^2}{1^2}\\\\F=6.67\times 10^{-11}$

It means that the order of the gravitational force is $10^{-11}$. Hence, the correct option is (d).

Answer 2

Hola ⚘⚘

Given:

• Distance betweew two objects of ordinary size is 1m

Tofind:

• The order of force of gravitational

Calculate:

Let us assume that each of the object masses are 1kg and separated by distance r.

• Mass (m1) = 1kg;
• Mass (m2) = 1kg;
• Distance of separation (r) = 1m.

>> F = Gm²/r²

where,

• F = force
• m = mass
• r = distance separated

>> F = ( 6.67*10^{-11}*1² ) / 1²

>> F = 6.67*10^{-11}

Hence, the order of gravitational force is 10^{-11}

∴ Option (d) 10^{-11} is correct [✓]