Question

The force on a particle of mass 10g is(10i+5j)N. If it starts from rest, what would be it's position at t=5s?

Answer 1

F = √(10)^2+(5)^2 = √125 = 5√5
so F = ma
a = 5√5/10 = √5 /2 = 1.18
s = ut + 1/2at^2
s = 1/2 x 1.18 x 5 x 5
= 14.75 m

Answer 2

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