Question

the force required to accelerate a body of mass 10gm from rest to 10m/s, in 10 seconds is
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Answer 1

Answer :

Mass of body = 10g = 0.01kg

Initial velocity = zero

Final velocity = 10m/s

Tome interval = 10s

We have to find magnitude of applied force$.$

★ As per newton's second law of motion force is defined as the rate of change of linear momentum.

• F = dp/dt

Force is a polar vector quantity as it has a point of application.

Momentum is measured as the product of mass and velocity.

• F = m (v - u) / t

F denotes force

m denotes mass

v denotes final velocity

u denotes initial velocity

t denotes time

By substituting the given values;

➝ F = m (v - u) / t

➝ F = 0.01 (10 - 0) / 10

➝ F = 0.01 × 10/10

➝ F = 0.01 N

Answer 2

____________________________________

$\fbox{given}$

Mass= 10 gram = 10 /1000 kg

time = 10sec

inital velocity= 0 m/sec

final velocity= 10m/sec

________________________________

$\fbox{to \: find}$

Force = ?

__________________________________

$⛄ \fbox{solution}$

In order to find the force we need to find acceleration first.

$♠acceleration= \frac{v - u}{t}$

$♠ acceleration= \frac{10 - 0}{10} = 1 \frac{m}{sec}$

According to Newton's second law of motion :

$♠force = mass \times accleration$

Force = 10 / 1000 x 1

$Force = 0.01 N$