The force required to impart to a car a velocity of 30m/s in 10 sec starting from rest if the mass of the car is
1500kg is –
a. -4500N, b. 4500N, c. 45000N, d. 450N.
Answers
Answered by
19
hi friend,
from newton second law of motion
f×t=m(v-u)
f=m(v-u)/t
=1500(30-0)/10
=4500N
I hope this will help u :)
from newton second law of motion
f×t=m(v-u)
f=m(v-u)/t
=1500(30-0)/10
=4500N
I hope this will help u :)
Answered by
26
HI there !!
Force = F
Mass = m = 1500 kg
Initial velocity = u = 0
Final velocity = v = 30 m/s
Force = m(v-u)/t
= 1500 x 30/10
= 4500 N
Force = F
Mass = m = 1500 kg
Initial velocity = u = 0
Final velocity = v = 30 m/s
Force = m(v-u)/t
= 1500 x 30/10
= 4500 N
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