Question

The formation of Glucose, C6H12O6 produces Ethyl alcohol and carbon dioxide. C6H12O6 -> 2C2H5OH + 2CO2 How many grams of Glucose are required to form 60g C2H5OH?​

Answer 1

Answer:

Answer and Explanation:

A.

Given Data:

The moles of glucose are 0.400 mol.

The chemical reaction is shown below.

C

6

H

12

O

6

→

2

C

2

H

5

O

H

(

a

q

)

+

2

C

O

2

(

g

)

C6H12O6→2C2H5OH(aq)+2CO2(g)

According to the above reaction, 1 mole of glucose gives 2 moles of carbon dioxide.

So, the moles of carbon dioxide are

2

×

0.400

m

o

l

=

0

.800

m

o

l

2×0.400mol=0.800mol.

Therefore, the moles of carbon dioxide are 0.800 mol.

B.

Given Data:

The mass of ethanol is 7.50 g.

The molar mass of ethanol is 46.07 g/mol.

The moles of ethanol can be calculated as shown below.

M

o

l

e

s

=

M

a

s

s

M

o

l

a

r

m

a

s

s

Moles=MassMolarmass

Substitute the respective values in the above equation.

M

o

l

e

s

=

7.50

g

46.07

g

/

m

o

l

=

0.162

m

o

l

Moles=7.50g46.07g/mol=0.162mol