The formation of Glucose, C6H12O6 produces Ethyl alcohol and carbon dioxide. C6H12O6 -> 2C2H5OH + 2CO2 How many grams of Glucose are required to form 60g C2H5OH?
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Answer:
Answer and Explanation:
A.
Given Data:
The moles of glucose are 0.400 mol.
The chemical reaction is shown below.
C
6
H
12
O
6
→
2
C
2
H
5
O
H
(
a
q
)
+
2
C
O
2
(
g
)
C6H12O6→2C2H5OH(aq)+2CO2(g)
According to the above reaction, 1 mole of glucose gives 2 moles of carbon dioxide.
So, the moles of carbon dioxide are
2
×
0.400
m
o
l
=
0
.800
m
o
l
2×0.400mol=0.800mol.
Therefore, the moles of carbon dioxide are 0.800 mol.
B.
Given Data:
The mass of ethanol is 7.50 g.
The molar mass of ethanol is 46.07 g/mol.
The moles of ethanol can be calculated as shown below.
M
o
l
e
s
=
M
a
s
s
M
o
l
a
r
m
a
s
s
Moles=MassMolarmass
Substitute the respective values in the above equation.
M
o
l
e
s
=
7.50
g
46.07
g
/
m
o
l
=
0.162
m
o
l
Moles=7.50g46.07g/mol=0.162mol
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