Question

The formation of oxide ion O²⁻(g), from oxygen atom requires
first an exothermic and then an endothermic step as shown
below
O (g) + e⁻ → O⁻ (g); ∆H⁻ = – 141 kJ mol⁻¹
O⁻ (g) + e⁻ → O²⁻ (g); ∆H⁻ = + 780 kJ mol⁻¹
Thus, process of formation of O²⁻ in gas phase is
unfavourable even though O²⁻ is isoelectronic with neon. It
is due to the fact that
(a) oxygen is more electronegative
(b) addition of electron in oxygen results in larger size of
the ion
(c) electron repulsion outweighs the stability gained by
achieving noble gas configuration
(d) O⁻ ion has comparatively smaller size than oxygen atom

Answer 1

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