The formula for calculating single phase ac power is
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To Find...Direct CurrentAlternating CurrentSingle PhaseTwo-Phase* Four-WireThree PhaseAmperes when Horsepower is knownHP x 746E x EFFHP x 746E x EFF x PFHP x 7462 x E x EFF x PFHP x 746E x EFF x PF x 1.73 Amperes when Kilowatts are knownKW x 1000EKW x 1000E x PFKW x 10002 x E x PFKW x 1000E x PF x 1.73 Amperes when "KVA" is known KVA x 1000EKVA x 10002 x EKVA x 1000E x 1.73 KilowattsE x I1000E x I x PF1000I x E x 2 x PF1000E x I x 1.73 x PF1000 Kilovolt-Amperes "KVA"
I x E1000I x E x 21000E x I x 1.731000 Horsepower (Output)E x I x EFF746E x I x EFF x PF746I x E x 2 x EFF x PF746E x I x EFF x PF x 1.73746E = Voltage / I = Amps / PF = Power Factor / EFF = Efficiency / HP = Horsepower
NOTE: Direct Current formulae do not use (PF, 2, or 1.73); Single phase formulas do not use (2 or 1.73); Two phase-four wire formulas do not use (1.73);
Three phase formulas do not use (2)
* For three-wire, two phase circuits, the current in the common conductor is 1.41 times the current in either of the other two conductors.
I x E1000I x E x 21000E x I x 1.731000 Horsepower (Output)E x I x EFF746E x I x EFF x PF746I x E x 2 x EFF x PF746E x I x EFF x PF x 1.73746E = Voltage / I = Amps / PF = Power Factor / EFF = Efficiency / HP = Horsepower
NOTE: Direct Current formulae do not use (PF, 2, or 1.73); Single phase formulas do not use (2 or 1.73); Two phase-four wire formulas do not use (1.73);
Three phase formulas do not use (2)
* For three-wire, two phase circuits, the current in the common conductor is 1.41 times the current in either of the other two conductors.
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