Question

the four angles of a quadrilateral are 2(x-10);(x+30),(x+50)and 2x:find all the four angles

Answer 1

sum of all angles of quad are 360..so.. (2x-20)+(x+30)+(x+50)+2x=360...2x-20+x+30+x+50+2x=360.....2x+x+x+2x-20+30+50=360....6x+60=360.....6x=360-60....6x=300....x=300/6...x=50...so angles are: 1.=2x-20.....=2*50-20..=100-20........=80..2.=x+30....=50+30....=80...3.=x+50.=50+50.=100..4.=2x=2*50=100....you can check by using property of sum of opp. angles of quad which is 180...<1+<3=180; <2+<4=180...

Answer 2

2(x-10)+(x+30)+(x+50)+ 2x=2x-20+x+30+x+50+2x
     -2x -x-x-2x                    = -20+30+50
                                -6x     =60
                                        x=  60/-6
                                          = -10
2(x-10)=2(-10-10)
           =2-20
           = -18°
x+30=-10+30
        =20°
x+50= -10+50
        =40°
2x=2*-10
    = -20°
hope it helps
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