The four angles of a quadrilateral
are (x - 10)°, (x + 20)°, (2x + 50°)
and 2xº. Find the four angles.
pls solve on paper
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(x-10°)+(x+20°)+(2x+50°)+2x=360°
6x+60°=360°
6x=360°-60°
6x=300°
x=50°
frist angle=(x-10°)=(50°-10°)=40°
second angle=(x+20°)=50°+20°)=70°
third angle=(2x+50°)=(2*50+50°)=150°
fourth angle=2x°=2*50°=100°
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